Let's see if ANYONE can answer this question. On the voltage regulator in the 1955 Buick (Century 4-door hardtop, series 63 with 322 v-8, dynaflow tranny) there are three terminals. The one in the middle has a white wire on it that comes from the generator. That white wire has a smaller green wire attached to it that runs from that same terminal to the starter relay just below the voltage regulator on the inner fender. I am assuming this is part of the starter cut-off circuit so the starter does not engage when stepping on the pedal after the engine is running. May not be correct, but that's my assumption. Here's my question and where it gets tricky. I had my generator converter to an alternator. Cool part is, according to the instructions and diagram that guy who did the conversion sent me, I do not have to alter the stock wiring EXCEPT for moving that white wire that comes from the generator from the middle voltage regulator terminal, to the left "B" (battery) terminal on the voltage regulator. Wired this way the alternator charges the battery (I tested while car running and it works. Attached in the stock position battery not charging, attached to the "B" terminal, battery charges.) So, does that little green wire from the starter relay come with the white one, or does it stay on the middle terminal all by itself? Wish I knew more about how the circuit works. Will this change make the cut off circuit not work? If so, how do I get around this? Anyone know anything about this???? Thanks. -Al